milly017
milly017 milly017
  • 03-04-2019
  • Mathematics
contestada

if f(x)=-4x^2-6x-1 and g(x)=-x^2-5x+3, fine (f-g)(x)

Respuesta :

gmany
gmany gmany
  • 06-04-2019

Answer:

[tex]\large\boxed{(f-g)(x)=-3x^2-x-4}[/tex]

Step-by-step explanation:

[tex](f-g)(x)=f(x)-g(x)[/tex]

[tex]f(x)=-4x^2-6x-1,\ g(x)=-x^2-5x+3\\\\(f-g)(x)=(-4x^2-6x-1)-(-x^2-5x+3)\\\\(f-g)(x)=-4x^2-6x-1-(-x^2)-(-5x)-3\\\\(f-g)(x)=-4x^2-6x-1+x^2+5x-3\qquad\text{combine like terms}\\\\(f-g)(x)=(-4x^2+x^2)+(-6x+5x)+(-1-3)\\\\(f-g)(x)=-3x^2-x-4[/tex]

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