Respuesta :

mhanifa

Step-by-step explanation:

See the solution for each part

1)

  • f(-2) = - 3(-2) - 6 = 6 - 6 = 0

2)

  • g(3) = 3² + 4 = 9 + 4 = 13

3)

  • f(g(x)) = -3(x² + 4) - 6 = - 3x² - 12 - 6 = - 3x² - 18

4)

  • f(g(3)) = f(13) = - 3(13) - 6 = - 39 - 6 = - 45

5)

  • x = - 3f⁻¹(x) - 6
  • 3f⁻¹(x) = - x - 6
  • 3f⁻¹(x) = -(x + 6)
  • f⁻¹(x) =  - (x + 6)/3
  • f(x)=-3x-6
  • g(x)=x²+4

Now

  • f(-2)=-3(-2)-6=6-6=0
  • g(3)=3²+4=9+4=13
  • f(g(x))=-3(x²+4)-6=-3x²-12-6=-3x²-18
  • f(g(3))=-3(3)^2-18=-27-18=-45

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